Answer: A
Principal \((p) = 1250\) rupees
Time \((t) = \cfrac{146}{365}=\cfrac{2}{5}\) years
Interest rate \((r) = 4\%\)
\(\therefore\) Total interest amount \((I) = \cfrac{ptr}{100}\)
\(= \cfrac{1250 × \cfrac{2}{5} × 4}{100}\)
\(= \cfrac{\cancel{1250}\cancel{50}10 × \cfrac{2}{\cancel5} × \cancel4}{\cancel{100}\cancel{25}}\)
\(= 20\) rupees.
\(\therefore\) Maturity amount = \((1250 + 20)\) rupees = \(1270\) rupees.
Principal \((p) = 1250\) rupees
Time \((t) = \cfrac{146}{365}=\cfrac{2}{5}\) years
Interest rate \((r) = 4\%\)
\(\therefore\) Total interest amount \((I) = \cfrac{ptr}{100}\)
\(= \cfrac{1250 × \cfrac{2}{5} × 4}{100}\)
\(= \cfrac{\cancel{1250}\cancel{50}10 × \cfrac{2}{\cancel5} × \cancel4}{\cancel{100}\cancel{25}}\)
\(= 20\) rupees.
\(\therefore\) Maturity amount = \((1250 + 20)\) rupees = \(1270\) rupees.