Q.Given two parallel chords AB and CD, each of length 16 cm, and the radius of the circle is 10 cm, what is the distance between the two chords? (a) 12 cm (b) 16 cm (c) 20 cm (d) 5 cm
Answer: A
Given that, AB=CD=16 cm and OB=OD=10 cm
From the right-angled triangle ∆POB,
OB\(^2\)=OP\(^2\)+PB\(^2\)
or, 10\(^2\)=OP\(^2\)+\((\frac{16}{2})^2\)
or, OP\(^2\)=100-64
or, OP=\(\sqrt{36}\)=6
∴PQ=6×2=12 cm
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