Q.If the surface area of a sphere is \(A\) and its volume is \(V\), then find the value of \(\cfrac{A^3}{V^2}\).

Let the radius of the sphere be \(r\) units. ∴ Surface area of the sphere, \(A = 4πr^2\) square units And volume of the sphere, \(V = \cfrac{4}{3}πr^3\) cubic units Now, \(\cfrac{A^3}{V^2} = \cfrac{(4πr^2)^3}{\left(\cfrac{4}{3}πr^3\right)^2}\) \(= \cfrac{64π^3r^6}{\cfrac{16}{9}π^2r^6} = 4 × 9π = 36π\) ∴ \(\cfrac{A^3}{V^2} = 36π\)
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