Cross-sectional area of the pipe = \(3\) sq cm = \(\frac{3}{100 \times 100}\) sq meters Speed of water flow through the pipe = \(7.7\) km/hour = \(7700\) meters/hour Time taken to fill the reservoir = \(3\frac{1}{2}\) hours = \(\frac{7}{2}\) hours \(\therefore\) Volume of the reservoir \(= \frac{3}{100 \times 100} \times 7700 \times \frac{7}{2}\) cubic meters \(= 8.085\) cubic meters