Q.The heights of two pillars are 180 meters and 60 meters respectively. If the angle of elevation to the top of the second pillar from the base of the first pillar is 30°, then find the angle of elevation to the top of the first pillar from the base of the second pillar.

Let’s assume two pillars: AB = 180 meters and CD = 60 meters. From the base of the first pillar (point B), the angle of elevation to the top of the second pillar (point C) is ∠CBD = 30°. We need to find the angle of elevation ∠ADB from the base of the second pillar (point D) to the top of the first pillar (point A). Let ∠ADB = θ. From the right-angled triangle CBD: \[ \tan 30^\circ = \frac{CD}{BD} \Rightarrow \frac{1}{\sqrt{3}} = \frac{CD}{BD} \Rightarrow BD = CD \cdot \sqrt{3} \Rightarrow BD = 60\sqrt{3} \] From the right-angled triangle ABD: \[ \tan ∠ADB = \frac{AB}{BD} \Rightarrow \tan θ = \frac{180}{60\sqrt{3}} \Rightarrow \tan θ = \sqrt{3} \Rightarrow \tan θ = \tan 60^\circ \Rightarrow θ = 60^\circ \] ∴ The angle of elevation from the base of the second pillar to the top of the first pillar is 60°
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