Substituting \(x = 0\) into the equation \(8x^2 + 7x = 0\): \[ 8 \cdot (0)^2 + 7 \cdot 0 = 0 \quad [The equation is satisfied by 0] \] Substituting \(x = -2\) into the equation \(8x^2 + 7x = 0\): \[ 8 \cdot (-2)^2 + 7 \cdot (-2) = 8 \cdot 4 - 14 = 32 - 14 = 18 \quad [≠ 0; \;\therefore\; the equation is not satisfied by -2] \] Therefore, 0 can be a root of the quadratic equation \(8x^2 + 7x = 0\), but -2 cannot be.
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