Answer: A
∴ Hypotenuse = \(\sqrt{a^2 + b^2}\)
∴ Area, \(\cfrac{1}{2} ab = \cfrac{1}{2} \sqrt{a^2 + b^2} \times p\)
or, \(ab = p \sqrt{a^2 + b^2}\)
or, \(a^2 b^2 = p^2 (a^2 + b^2)\)
or, \(\cfrac{1}{p^2} = \cfrac{a^2 + b^2}{a^2 b^2} = \cfrac{1}{b^2} + \cfrac{1}{a^2}\).
∴ Hypotenuse = \(\sqrt{a^2 + b^2}\)
∴ Area, \(\cfrac{1}{2} ab = \cfrac{1}{2} \sqrt{a^2 + b^2} \times p\)
or, \(ab = p \sqrt{a^2 + b^2}\)
or, \(a^2 b^2 = p^2 (a^2 + b^2)\)
or, \(\cfrac{1}{p^2} = \cfrac{a^2 + b^2}{a^2 b^2} = \cfrac{1}{b^2} + \cfrac{1}{a^2}\).