Let the original length of each edge of the cube be \(x\) units. If each edge is reduced by 50%, the new edge length becomes: \(x - 50\%\text{ of }x = x - \cfrac{50x}{100} = x - \cfrac{x}{2} = \cfrac{x}{2}\) units The volume of the original cube = \(x^3\) cubic units The volume of the reduced cube = \((\cfrac{x}{2})^3 = \cfrac{x^3}{8}\) cubic units ∴ The ratio of the volumes of the original cube to the reduced cube is: \(x^3 : \cfrac{x^3}{8} = 1 : \cfrac{1}{8} = 8 : 1\)