Q.In triangle \( \triangle ABC \), AD is a median. A straight line parallel to side BC intersects sides AB, AD, and AC at points P, O, and Q respectively. What is the ratio \( PO : OQ \)? (a) 1:2 (b) 2:3 (c) 1:1 (d) None of the above
Answer: C
In triangle \( \triangle ABD \), PO is parallel to BD ∴ \( \frac{PO}{BD} = \frac{AO}{AD} \) Again, in triangle \( \triangle ADC \), OQ is parallel to DC ∴ \( \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} \) ⇒ \( \frac{PO}{OQ} = \frac{DC}{BD} = 1 \) [because BD = DC] ∴ PO : OQ = 1 : 1
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