Answer: C
In triangle \( \triangle ABD \), PO is parallel to BD ∴ \( \frac{PO}{BD} = \frac{AO}{AD} \) Again, in triangle \( \triangle ADC \), OQ is parallel to DC ∴ \( \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} \) ⇒ \( \frac{PO}{OQ} = \frac{DC}{BD} = 1 \) [because BD = DC] ∴ PO : OQ = 1 : 1
In triangle \( \triangle ABD \), PO is parallel to BD ∴ \( \frac{PO}{BD} = \frac{AO}{AD} \) Again, in triangle \( \triangle ADC \), OQ is parallel to DC ∴ \( \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} = \frac{AO}{AD} \) ∴ \( \frac{PO}{BD} = \frac{OQ}{DC} \) ⇒ \( \frac{PO}{OQ} = \frac{DC}{BD} = 1 \) [because BD = DC] ∴ PO : OQ = 1 : 1