Q.If \(25x^2 - 20ax + b\) is a perfect square, which of the following relations is true? (a) \(b=2a^2\) (b) \(b=4a^2\) (c) \(b=a^2\) (d) \(b=3a^2\)
Answer: B
If \(25x^2 - 20ax + b\) is a perfect square, then the roots of the equation \(25x^2 - 20ax + b = 0\) will be equal. That means the discriminant will be zero. \(\therefore (-20a)^2 - 4 \times 25 \times b = 0\) or, \(400a^2 - 100b = 0\) or, \(100b = 400a^2\) or, \(b = 4a^2\)
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