Q.If \( x \propto yz \) and \( y \propto zx \), then show that \( z \ne 0 \) is a constant.

Given: \(x \propto yz\) ⇒ \(x = kyz\) Also, \(y \propto zx\) ⇒ \(y = mzx = m \cdot z \cdot kyz\) (where \(k, m\) are non-zero distinct constants) So, \[ kmyz^2 = y \Rightarrow z^2 = \frac{1}{km} \Rightarrow z = \sqrt{\frac{1}{km}} \] Since \(k\) and \(m\) are non-zero constants, ∴ \(z\) is a non-zero constant.
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