Q.If \( \sin\theta + \csc\theta = 2 \), then what is the value of \( \sin^2\theta + \csc^2\theta \)? (a) 1 (b) 2 (c) 4 (d) \cfrac{3}{4}
Answer: B
\(\sin^2 \theta + \csc^2 \theta\) \(= (\sin \theta + \csc \theta)^2 - 2\sin\theta \csc\theta\) \(= 2^2 - 2 \times \cancel{\sin\theta} \times \frac{1}{\cancel{\sin\theta}}\) \(= 4 - 2 = 2\)
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