Q.In triangle ABC, the circumcenter is O. If \(\angle\)BAC = 85° and \(\angle\)BCA = 75°, then what is the measure of \(\angle\)OAC? (a) 70° (b) 40° (c) 110° (d) 140°
Answer: A
In triangle ABC, \(\angle\)ABC = 180° – (\(\angle\)BAC + \(\angle\)BCA) = 180° – (85° + 75°) = 20° \(\therefore\) Central angle \(\angle\)AOC = 2 × \(\angle\)ABC = 2 × 20° = 40° Now, in triangle AOC, AO = OC \(\therefore \angle\)OAC = \(\angle\)OCA = \(\frac{1}{2}\)(180° – 40°) = 70° \(\therefore \angle\)OAC = 70° (Answer)
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