Q.If \(x : a = y : b = z : c\), then show that \((a^2 + b^2 + c^2)(x^2 + y^2 + z^2) = (ax + by + cz)^2\)

Given: \(x : a = y : b = z : c\) Let \(\cfrac{x}{a} = \cfrac{y}{b} = \cfrac{z}{c} = k\), where \(k ≠ 0\) ∴ \(x = ak\), \(y = bk\), and \(z = ck\) **Left-hand side:** \((a^2 + b^2 + c^2)(x^2 + y^2 + z^2)\) \(= (a^2 + b^2 + c^2)(a^2k^2 + b^2k^2 + c^2k^2)\) \(= (a^2 + b^2 + c^2) \cdot k^2(a^2 + b^2 + c^2)\) \(= k^2(a^2 + b^2 + c^2)^2\) **Right-hand side:** \((ax + by + cz)^2\) \(= (a \cdot ak + b \cdot bk + c \cdot ck)^2\) \(= (a^2k + b^2k + c^2k)^2\) \(= k^2(a^2 + b^2 + c^2)^2\) ∴ Left-hand side = Right-hand side (Proved)
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