Answer: A
Assume that the principal \((p) = 8x\) rupees
And the interest-principal \(= 9x\) rupees
Interest \((I) = (9x - 8x) = x\) rupees
Time \((t) = 1\) year
∴ Interest rate \((r) = \cfrac{100 × I}{pt}\)
\(= \cfrac{100 × x}{8x × 1} = \cfrac{25}{2} = 12\cfrac{1}{2}\%\)
Assume that the principal \((p) = 8x\) rupees
And the interest-principal \(= 9x\) rupees
Interest \((I) = (9x - 8x) = x\) rupees
Time \((t) = 1\) year
∴ Interest rate \((r) = \cfrac{100 × I}{pt}\)
\(= \cfrac{100 × x}{8x × 1} = \cfrac{25}{2} = 12\cfrac{1}{2}\%\)