\((a^2 + b^2) x^2 + 2(ac + bd)x\) \(+(c^2 + d^2) = 0 \)
Since the roots of the quadratic equation are equal, the discriminant must be \(0\).
\(ā“ {2(ac + bd)}^2 - 4(a^2 + b^2)(c^2 + d^2) = 0\)
Or, \(4(a^2 c^2 + 2abcd + b^2 d^2)\)
\(- 4(a^2 c^2 + a^2 d^2 + b^2 c^2 + b^2 d^2) = 0\)
Or, \(4a^2 c^2 + 8abcd + 4b^2 d^2 - 4a^2 c^2 - 4a^2 d^2\)
\(- 4b^2 c^2 - 4b^2 d^2 = 0\)
Or, \(-4a^2 d^2 + 8abcd - 4b^2 c^2 = 0\)
Or, \(a^2 d^2 - 2abcd + b^2 c^2 = 0\)
Or, \((ad)^2 - 2.ad.bc + (bc)^2 = 0\)
Or, \((ad - bc)^2 = 0\)
Or, \(ad - bc = 0\)
Or, \(ad = bc\)
Or, \(\cfrac{a}{b} = \cfrac{c}{d}\) (Proved).