Q.The bisectors of \(\angle\)A and \(\angle\)B of parallelogram ABCD intersect at point O. What is the measure of \(\angle\)AOB? (a) 30° (b) 60° (c) 90° (d) 45°
Answer Not Defined

In parallelogram ABCD, \(\angle\)A + \(\angle\)B = 180° ∴ \(\frac{1}{2}\)(\(\angle\)A + \(\angle\)B) = 90° That means, in triangle ABO, \(\angle\)OAB + \(\angle\)OBA = 90° ∴ The remaining angle \(\angle\)AOB = 180° − 90° = 90°
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