Let the length of the corresponding side in the second triangle be \(x\) cm. \[ \therefore \cfrac{9}{x} = \cfrac{27}{16} \Rightarrow 27x = 9 \times 16 \Rightarrow x = \cfrac{\cancel{9} \times 16}{\cancel{27} \times 3} \Rightarrow x = 5\cfrac{1}{3} \] \(\therefore\) The length of the corresponding side in the second triangle is \(5\cfrac{1}{3}\) cm.