Q.The perimeters of two similar triangles are 27 cm and 16 cm respectively. If one side of the first triangle is 9 cm, then find the length of the corresponding side of the second triangle.

Let the length of the corresponding side in the second triangle be \(x\) cm. \[ \therefore \cfrac{9}{x} = \cfrac{27}{16} \Rightarrow 27x = 9 \times 16 \Rightarrow x = \cfrac{\cancel{9} \times 16}{\cancel{27} \times 3} \Rightarrow x = 5\cfrac{1}{3} \] \(\therefore\) The length of the corresponding side in the second triangle is \(5\cfrac{1}{3}\) cm.
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