Answer: C
Since the perpendicular drawn from the center of a circle bisects the chord, \(D\) is the midpoint of \(QR\).
Now, in \(\triangle PQR\),
\(O\) is the midpoint of \(PR\), and \(D\) is the midpoint of \(QR\).
\(\therefore PQ = 2 \times OD = 2 \times 4\) cm = 8 cm.
Since the perpendicular drawn from the center of a circle bisects the chord, \(D\) is the midpoint of \(QR\).
Now, in \(\triangle PQR\),
\(O\) is the midpoint of \(PR\), and \(D\) is the midpoint of \(QR\).
\(\therefore PQ = 2 \times OD = 2 \times 4\) cm = 8 cm.