Q.Two chords, \(AB\) and \(CD\), of a circle with center \(O\), intersect at point \(P\). If \(\angle APC = 40°\), find the value of \(\angle AOC + \angle BOD\). (a) 60° (b) 80° (c) 120° (d) None of these
Answer: B
\(B\) and \(C\) are joined.
In \(\triangle BCP\), \(\angle PBC + \angle PCB =\) the exterior angle \(\angle APC\).
or, \(\angle ABC + \angle DCB = 40^\circ\).
or, \(\cfrac{1}{2}\angle AOC + \cfrac{1}{2}\angle BOD = 40^\circ\).
or, \(\angle AOC + \angle BOD = 80^\circ\).
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