In triangle ∆ABC, ∠B = 90°, AC = √13 cm, and AB + BC = 5 cm. Find the value of (cos A + cos C).

Q.In triangle ∆ABC, ∠B = 90°, AC = √13 cm, and AB + BC = 5 cm. Find the value of (cos A + cos C).

In triangle ∆ABC, ∠B = 90° ∴ cos A + cos C = \(\frac{AB}{AC} + \frac{BC}{AC}\) = \(\frac{AB + BC}{AC} = \frac{5}{\sqrt{13}}\)