Q.In the center circle O, AB is a diameter. C is any point on the circumference of the circle where AC = 3 cm and BC = 4 cm. Find the length of AB. (a) 3 cm (b) 4 cm (c) 5 cm (d) 7 cm
Answer: C
Since \(\angle\) ACB = 90° (semicircular angle),
In the right-angled triangle \(\Delta ABC\),

AB\(^2\) = AC\(^2\) + BC\(^2\) = 3\(^2\) + 4\(^2\) = 25,
Thus, AB = 5 cm.
Similar Questions