Answer: C
Since \(\angle\) ACB = 90° (semicircular angle),
In the right-angled triangle \(\Delta ABC\),
AB\(^2\) = AC\(^2\) + BC\(^2\) = 3\(^2\) + 4\(^2\) = 25,
Thus, AB = 5 cm.
Since \(\angle\) ACB = 90° (semicircular angle),
In the right-angled triangle \(\Delta ABC\),
AB\(^2\) = AC\(^2\) + BC\(^2\) = 3\(^2\) + 4\(^2\) = 25,
Thus, AB = 5 cm.