Q.If the equation \((x+2)^3 = x(x-1)^2\) is expressed in the form of the quadratic equation \(ax^2 + bx + c = 0\) \((a ≠ 0)\), the coefficient of \(x^0\) (the constant term) will be. (a) -8 (b) -1 (c) 3 (d) 8
Answer: D
\((x+2)^3 = x(x-1)^2\)
Or, \(x^3 + 3x^2 \cdot 2 + 3x \cdot 2^2 + 2^3\)

\(= x(x^2 - 2x + 1)\)

Or, \(x^3 + 6x^2 + 12x + 8 - x^3\)

\(+ 2x^2 - x = 0\)

Or, \(8x^2 + 11x + 8 = 0\)

∴ The coefficient of \(x^0\), i.e., the constant term, is \(8\).
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