\(x ∝ y^2\) i.e., \(x = ky^2 \quad \text{---(i)}\) [where \(k\) is a non-zero constant] Substituting \(y = 2a\) and \(x = a\), we get: \(a = k \cdot (2a)^2\) i.e., \(k = \cfrac{a}{4a^2} = \cfrac{1}{4a}\) Substituting the value of \(k\) into equation (i), we get: \(x = \cfrac{1}{4a} y^2\) i.e., \(y^2 = 4ax\) (Proved)