Q.In triangle ABC, \(\angle\)ABC is a right angle, and AB = 5 cm, BC = 12 cm. What is the radius of the circumcircle of triangle ABC?

In triangle ABC: \(AC^2 = AB^2 + BC^2 = 5^2 + 12^2 = 25 + 144 = 169\) ∴ \(AC = \sqrt{169} = 13\) cm ∴ Radius of the circumcircle = \(\frac{13}{2}\) cm = 6.5 cm
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