Q.If the combined mean of the following frequency distribution table is 54, determine the value of \(K\):
Class Interval0-2020-4040-6060-8080-100
Frequency711K913

Class IntervalFrequency (\(f_i\))Class Midpoint (\(x_i\))\(f_ix_i\)
0-2071070
20-401130330
40-60\(k\)50\(50k\)
60-80970630
80-10013901170
Total\(\sum f_i=\) \(40+k\)\(\sum f_ix_i=\) \(2200+50k\)
\(\therefore\) According to the given condition, the combined mean is \(54\).
Thus, \(\cfrac{\sum x_i f_i}{\sum f_i}=54\)
or, \(\cfrac{2200+50k}{40+k}=54\)
or, \(2160+54k=2200+50k\)
or, \(54k-50k=2200-2160\)
or, \(4k=40\)
or, \(k=10\)

\(\therefore\) The required value of \(k=10\).
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