Let the time taken be \(x\) minutes. Radius of the pipe \((r) = \frac{5.6}{2}\) cm = 2.8 cm \(= \frac{28}{1000}\) meters. \(\therefore\) Volume of water flowing through the pipe per minute \(= \pi \times \left(\frac{28}{1000}\right)^2 \times 200\) cubic meters \(= \frac{22 \times 28}{250 \times 5}\) cubic meters Now, volume of \(\frac{5}{8}\) of the tank \(= 2.8 \times 2.2 \times 1.6 \times \frac{5}{8}\) cubic meters \(= \frac{28 \times 22 \times 16 \times 5}{8 \times 1000}\) cubic meters \(\therefore \frac{22 \times 28}{250 \times 5} \times x = \frac{28 \times 22 \times 16 \times 5}{8 \times 1000}\) i.e., \(x = \frac{25}{2} = 12\frac{1}{2}\) \(\therefore\) It will take \(12\frac{1}{2}\) minutes to fill \(\frac{5}{8}\) of the tank.