Q.For the quadratic equation \(x^2 - bkx + 5 = 0\), if one of the roots is 5, then the value of \(k\) will be. (a) \(-\cfrac{1}{2}\) (b) -1 (c) 1 (d) 0
Answer: C
In the quadratic equation \(x^2 - 6kx + 5 = 0\), by substituting \(x = 5\), we get:
\(5^2 - 6k \times 5 + 5 = 0\)
or, \(25 - 30k + 5 = 0\)
or, \(-30k = -30\)
or, \(k = 1\).
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