The statement is false.
If the original radius is \(r\), then the new radius becomes \(\cfrac{r}{2}\), and if the original height is \(h\), then the new height becomes \(2h\). ∴ Original volume = \(\cfrac{1}{3} πr^2 h\) cubic units New volume = \[ = \cfrac{1}{3} π\left(\cfrac{r}{2}\right)^2 × 2h = \cfrac{1}{3} π \cfrac{r^2}{4} × 2h = \cfrac{1}{6} πr^2 h \] Which is not equal to the original volume.