Suppose the quadratic equation \(ax^2+bx+c=0\) has one root \(α\) and the other root \(2α\). \(∴ α+2α=-\cfrac{b}{a}\) or, \(3α=-\cfrac{b}{a}\) or, \(α=-\cfrac{b}{3a}\) Again, \(α \cdot 2α=\cfrac{c}{a}\) or, \(2α^2=\cfrac{c}{a}\) or, \(2×(-\cfrac{b}{3a})^2=\cfrac{c}{a}\) or, \(\cfrac{2b^2}{9a^2}=\cfrac{c}{a}\) or, \(2ab^2=9a^2 c\) or, \(2b^2=9ac\) (proved)