Let the two roots of the equation \(x^2 + x + 1 = 0\) be \(\alpha\) and \(\beta\). \(\therefore \alpha + \beta = -1\) and \(\alpha \beta = 1\) Now, if the roots are squared, the new equation will have roots \(\alpha^2\) and \(\beta^2\). Then, \(\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta\) \(= (-1)^2 - 2 \cdot 1 = 1 - 2 = -1\) And, \(\alpha^2 \beta^2 = (\alpha \beta)^2 = 1^2 = 1\) \(\therefore\) The new equation will be: \(x^2 - (\alpha^2 + \beta^2)x + (\alpha^2 \cdot \beta^2) = 0\) i.e., \(x^2 - (-1)x + 1 = 0\) i.e., \(x^2 + x + 1 = 0\) (Answer)