Q.AB and AC are two tangents drawn from point A to a circle with center O. The line OA intersects the chord BC (which joins the points of contact) at point M. If AM = 8 cm and BC = 12 cm, then what is the length of each tangent? (a) 8 cm (b) 10 cm (c) 12 cm (d) 16 cm
Answer: B
In the right-angled triangle \(\triangle ABM\): BM = \(\frac{1}{2}\) × BC = 6 cm AM = 8 cm \[ \therefore AB^2 = BM^2 + AM^2 = 6^2 + 8^2 = 36 + 64 = 100 \] \[ \therefore AB = \sqrt{100} = 10 \text{ cm} \] \[ \therefore AB = AC = 10 \text{ cm} \]
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