Answer: A
In the right-angled triangle \(\triangle\)AOP, OA = 5 cm, OP = 3 cm \(\therefore\) AP\(^2\) = OA\(^2\) − OP\(^2\) = 5\(^2\) − 3\(^2\) = 25 − 9 = 16 \(\therefore\) AP = \(\sqrt{16}\) cm = 4 cm \(\therefore\) AB = 2 × AP = 8 cm
In the right-angled triangle \(\triangle\)AOP, OA = 5 cm, OP = 3 cm \(\therefore\) AP\(^2\) = OA\(^2\) − OP\(^2\) = 5\(^2\) − 3\(^2\) = 25 − 9 = 16 \(\therefore\) AP = \(\sqrt{16}\) cm = 4 cm \(\therefore\) AB = 2 × AP = 8 cm