Let the interest on both loans become equal after \(x\) years from the first loan. \(\therefore\) Interest on the first loan \(= \frac{4000 \times x \times 7}{100}\) rupees For the second loan, the time is \((x - 1)\) years. Interest on the second loan \(= \frac{4000 \times (x - 1) \times 8}{100}\) rupees According to the question, \(\frac{4000 \times x \times 7}{100} = \frac{4000 \times (x - 1) \times 8}{100}\) i.e., \(7x = 8(x - 1)\) i.e., \(7x = 8x - 8\) i.e., \(-x = -8\) i.e., \(x = 8\) \(\therefore\) The interest on both loans will be equal 8 years after the first loan.