Q.A man takes a loan of ₹4,000 at 7% simple interest per annum, and exactly one year after the first loan, he takes a second loan of ₹4,000 at 4% simple interest per annum. After how many years from the first loan will the interest on both loans be equal?

Let the interest on both loans become equal after \(x\) years from the first loan. \(\therefore\) Interest on the first loan \(= \frac{4000 \times x \times 7}{100}\) rupees For the second loan, the time is \((x - 1)\) years. Interest on the second loan \(= \frac{4000 \times (x - 1) \times 8}{100}\) rupees According to the question, \(\frac{4000 \times x \times 7}{100} = \frac{4000 \times (x - 1) \times 8}{100}\) i.e., \(7x = 8(x - 1)\) i.e., \(7x = 8x - 8\) i.e., \(-x = -8\) i.e., \(x = 8\) \(\therefore\) The interest on both loans will be equal 8 years after the first loan.
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