Q.If \(x + y \propto x - y\), then show that \(x^3 + y^3 \propto x^3 - y^3\).

\(x + y \propto x - y\) i.e., \(x + y = k(x - y)\), where \(k\) is a non-zero constant i.e., \(\cfrac{x + y}{x - y} = k\) Now, adding and subtracting numerator and denominator: \[ \cfrac{x + y + x - y}{x + y - x + y} = \cfrac{2x}{2y} \] Let \(\cfrac{k + 1}{k - 1} = p\), Then, \(\cfrac{x}{y} = p\) Cubing both sides: \(\cfrac{x^3}{y^3} = p^3\) So, \[ \cfrac{x^3 + y^3}{x^3 - y^3} = \cfrac{p^3 + 1}{p^3 - 1} = \text{constant} \] \(\therefore x^3 + y^3 \propto x^3 - y^3\) (Proved)
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