Q.If the mean of the numbers \(x_1, x_2, x_3, x_4, ..., x_n\) is \(\bar{x}\), then the value of \((x_1 - \bar{x}) + (x_2 - \bar{x}) + (x_3 - \bar{x}) + ... + (x_n - \bar{x})\) will be — (a) 0 (b) 1 (c) 3 (d) 5
Answer: A
The mean of the numbers \(x_1, x_2, x_3, x_4, ..., x_n\) is \(\bar{x}\) \(\therefore \cfrac{x_1 + x_2 + x_3 + x_4 + ... + x_n}{n} = \bar{x}\) \(\therefore n\bar{x} = x_1 + x_2 + x_3 + x_4 + ... + x_n\) \((x_1 - \bar{x}) + (x_2 - \bar{x}) + (x_3 - \bar{x}) + ... + (x_n - \bar{x})\) = \((x_1 + x_2 + x_3 + x_4 + ... + x_n) - n\bar{x}\) = \(n\bar{x} - n\bar{x}\) = 0
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