Answer: D
In \(\triangle\)PQR,
\(\angle\)PRQ = Angle in a semicircle = 90°
And PR = RQ
\(\therefore \angle\)RPQ = \(\angle\)RQP = \(\frac{1}{2} \times\) 90° = 45°
In \(\triangle\)PQR,
\(\angle\)PRQ = Angle in a semicircle = 90°
And PR = RQ
\(\therefore \angle\)RPQ = \(\angle\)RQP = \(\frac{1}{2} \times\) 90° = 45°