Q.In a circle centered at O, PQ is a diameter; R is a point on the circle, and PR = RQ. Then, the measure of \(\angle\)RPQ is: ____? (a) 30° (b) 90° (c) 60° (d) 45°
Answer: D
In \(\triangle\)PQR,
\(\angle\)PRQ = Angle in a semicircle = 90°
And PR = RQ
\(\therefore \angle\)RPQ = \(\angle\)RQP = \(\frac{1}{2} \times\) 90° = 45°
Similar Questions