Answer: A
Given: \( r \sin\theta = \frac{7}{2} \) and \( r \cos\theta = \frac{7\sqrt{3}}{2} \) Therefore, \[ \frac{r \sin\theta}{r \cos\theta} = \frac{\frac{7}{2}}{\frac{7\sqrt{3}}{2}} \] Or, \[ \tan\theta = \frac{7}{2} \times \frac{2}{7\sqrt{3}} = \frac{1}{\sqrt{3}} \] Or, \[ \tan\theta = \tan 30^\circ \] Therefore, \[ \theta = 30^\circ \] Now, \[ r \sin\theta = \frac{7}{2} \] Or, \[ r \sin 30^\circ = \frac{7}{2} \] Or, \[ r \times \frac{1}{2} = \frac{7}{2} \] Or, \[ r = 7 \] Therefore, \[ r = 7,\quad \theta = 30^\circ \]
Given: \( r \sin\theta = \frac{7}{2} \) and \( r \cos\theta = \frac{7\sqrt{3}}{2} \) Therefore, \[ \frac{r \sin\theta}{r \cos\theta} = \frac{\frac{7}{2}}{\frac{7\sqrt{3}}{2}} \] Or, \[ \tan\theta = \frac{7}{2} \times \frac{2}{7\sqrt{3}} = \frac{1}{\sqrt{3}} \] Or, \[ \tan\theta = \tan 30^\circ \] Therefore, \[ \theta = 30^\circ \] Now, \[ r \sin\theta = \frac{7}{2} \] Or, \[ r \sin 30^\circ = \frac{7}{2} \] Or, \[ r \times \frac{1}{2} = \frac{7}{2} \] Or, \[ r = 7 \] Therefore, \[ r = 7,\quad \theta = 30^\circ \]