Let the radius of the base of the tent be \(r\) meters. Given that the curved surface area of the conical tent is: \[ \pi r l = 77 \] Substituting \(l = 7\): \[ \frac{22}{7} \times r \times 7 = 77 \Rightarrow r = \frac{77}{22} = \frac{7}{2} \] Therefore, the area of the base is: \[ \pi \left(\frac{7}{2}\right)^2 = \frac{22}{7} \times \frac{49}{4} = \frac{77}{2} = 38.5 \text{ square meters} \] So, the area of the base of the tent is 38.5 square meters.