If \(\alpha\) and \(\beta\) are the two roots of the quadratic equation \(3x^2 + 2x - 5 = 0\), then:
\(\alpha + \beta = -\cfrac{2}{3}\)
and \(\alpha\beta = \cfrac{-5}{3}\)
\(\therefore \cfrac{\alpha^2}{\beta} + \cfrac{\beta^2}{\alpha}\)
\(= \cfrac{\alpha^3 + \beta^3}{\alpha\beta}\)
\(= \cfrac{(\alpha + \beta)^3 - 3\alpha\beta(\alpha + \beta)}{\alpha\beta}\)
\(= \cfrac{(-\cfrac{2}{3})^3 - 3 \cdot \cfrac{-5}{3} \cdot \cfrac{-2}{3}}{\cfrac{-5}{3}}\)
\(= \cfrac{-\cfrac{8}{27} - \cfrac{10}{3}}{-\cfrac{5}{3}}\)
\(= \cfrac{\cfrac{-8 - 90}{27}}{-\cfrac{5}{3}}\)
\(= \cfrac{-98}{\cancel{27}9} \times -\cfrac{\cancel3}{5}\)
\(= \cfrac{98}{45} = 2\cfrac{8}{45}\)