The statement is false. Given: \(x = 2 + \sqrt{3}\) \[ \therefore \frac{1}{x} = \frac{1}{2 + \sqrt{3}} = \frac{2 - \sqrt{3}}{(2 + \sqrt{3)(2 - \sqrt{3})}} = \frac{2 - \sqrt{3}}{4 - 3} = 2 - \sqrt{3} \] \[ \therefore x + \frac{1}{x} = (2 + \sqrt{3}) + (2 - \sqrt{3}) = 4 \]