Answer Not Defined
Assume the radius of the circle is \(r\) meters. \(\therefore r^2 + r^2 = (4\sqrt{2})^2\) That is, \(2r^2 = 32\) So, \(r^2 = 16\) Therefore, \(r = 4\) \(\therefore\) The radius of the circle is 4 meters.
Assume the radius of the circle is \(r\) meters. \(\therefore r^2 + r^2 = (4\sqrt{2})^2\) That is, \(2r^2 = 32\) So, \(r^2 = 16\) Therefore, \(r = 4\) \(\therefore\) The radius of the circle is 4 meters.