Q.Bimal Babu lent a certain amount of money to one person at an annual simple interest rate of 8% for 4 years, and twice that amount to another person at an annual simple interest rate of 10% for the same duration. Bimal Babu received ₹960 more interest from the second person than from the first. Find the total amount of money Bimal Babu lent.

Let’s assume Bimal Babu lent ₹\(x\) to the first person and ₹\(2x\) to the second person. For the first person: - Principal \((P) = x\) - Time \((T) = 4\) years - Rate of interest \((R) = 8\%\) - Simple Interest \((I) = \frac{PTR}{100} = \frac{x \times 4 \times 8}{100} = \frac{8x}{25}\) ### For the second person: - Principal \((P) = 2x\) - Time \((T) = 4\) years - Rate of interest \((R) = 10\%\) - Simple Interest \((I) = \frac{PTR}{100} = \frac{2x \times 4 \times 10}{100} = \frac{4x}{5}\) ### According to the condition: The second person paid ₹960 more interest than the first. \[ \frac{4x}{5} - \frac{8x}{25} = 960 \Rightarrow \frac{20x - 8x}{25} = 960 \Rightarrow \frac{12x}{25} = 960 \Rightarrow x = 960 \times \frac{25}{12} = 2000 \] ### Therefore: Total amount lent = \(x + 2x = 3x = 3 \times 2000 = ₹6000\) Bimal Babu lent a total of ₹6000.
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