Q.If the combined mean of \(n\) quantities is \(\bar{x}\), and the sum of the first \((n-1)\) quantities is \(k\), then the \(n\)th quantity will be — (a) \(k+n\) (b) \(\bar{x}+k\) (c) \(\bar{x}-k\) (d) \(n\bar{x}-k\)
Answer: D
The combined mean of \(n\) quantities is \(\bar{x}\) \(\therefore\) The sum of \(n\) quantities is \(n\bar{x}\) If the sum of the first \((n-1)\) quantities is \(k\), then the \(n\)th quantity will be \(n\bar{x} - k\)
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