Q.In \(\triangle\)ABC, \(\angle\)ABC = 90°, and BD \(\bot\) AC. If BD = 6 cm and AD = 4 cm, then what is the length of CD?
From the diagram, we get \(\triangle\) ADB ~ \(\triangle\) BDC
\(∴ \cfrac{AD}{BD}=\cfrac{BD}{CD}\)
Or, \(\cfrac{4}{6}=\cfrac{6}{CD}\)
Or, \(CD=\cfrac{6×6}{4}=9\)