Q.The volume of a right circular cone is \(V\) cubic units. If the area of the base is \(A\) square units and the height is \(H\) units, then find the value of \(\frac{AH}{V}\).
If the radius of the base of a right circular cone is \(r\), then
\[
\pi r^2 = A
\]
Also,
\[
\frac{1}{3} \pi r^2 H = V
\]
Substituting \(\pi r^2 = A\), we get
\[
\frac{1}{3} AH = V
\]
Therefore,
\[
\frac{AH}{V} = 3 \quad \text{(Answer)}
\]