Q.The volume of a right circular cone is \(V\) cubic units. If the area of the base is \(A\) square units and the height is \(H\) units, then find the value of \(\frac{AH}{V}\).

If the radius of the base of a right circular cone is \(r\), then \[ \pi r^2 = A \] Also, \[ \frac{1}{3} \pi r^2 H = V \] Substituting \(\pi r^2 = A\), we get \[ \frac{1}{3} AH = V \] Therefore, \[ \frac{AH}{V} = 3 \quad \text{(Answer)} \]
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