Let the five numbers be \(a, b, c, d, e\) \(\therefore a + b + c + d = 26 \times 4 = 104\) — (i) and \(b + c + d + e = 25 \times 4 = 100\) — (ii) Subtracting equation (ii) from equation (i), we get: \(a - e = 104 - 100 = 4\) \(\therefore\) The difference between the first and the last number is 4.