Q.If the average of the first four numbers out of five is 26, and the average of the last four numbers is 25, then find the difference between the first and the last number.

Let the five numbers be \(a, b, c, d, e\) \(\therefore a + b + c + d = 26 \times 4 = 104\) — (i) and \(b + c + d + e = 25 \times 4 = 100\) — (ii) Subtracting equation (ii) from equation (i), we get: \(a - e = 104 - 100 = 4\) \(\therefore\) The difference between the first and the last number is 4.
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