Answer: A
Principal \((p) = x\) rupees Rate of interest \((r) = 6\%\) Interest amount \((I) = \frac{9x}{25}\) rupees Time \((t) = \frac{100 \times I}{pr}\) \[ = \frac{100 \times \frac{9x}{25}}{x \times 6} = \frac{4 \times 9x}{x \times 6} = 6 \text{ years} \]
Principal \((p) = x\) rupees Rate of interest \((r) = 6\%\) Interest amount \((I) = \frac{9x}{25}\) rupees Time \((t) = \frac{100 \times I}{pr}\) \[ = \frac{100 \times \frac{9x}{25}}{x \times 6} = \frac{4 \times 9x}{x \times 6} = 6 \text{ years} \]