Answer: B
For the quadratic equation 5x\(^2\)+9x+3=0, if the roots are α and β
Therefore, \(α+β=-\cfrac{9}{5}\)
and \(αβ=\cfrac{3}{5}\)
∴ \(\cfrac{1}{α}+\cfrac{1}{β}\)=\(\cfrac{β+α}{αβ}\)=\(\cfrac{\cfrac{-9}{5}}{\cfrac{3}{5}}\)=\(\cfrac{-9}{5}×\cfrac{5}{3}\)=-3
For the quadratic equation 5x\(^2\)+9x+3=0, if the roots are α and β
Therefore, \(α+β=-\cfrac{9}{5}\)
and \(αβ=\cfrac{3}{5}\)
∴ \(\cfrac{1}{α}+\cfrac{1}{β}\)=\(\cfrac{β+α}{αβ}\)=\(\cfrac{\cfrac{-9}{5}}{\cfrac{3}{5}}\)=\(\cfrac{-9}{5}×\cfrac{5}{3}\)=-3