Q.If, tanθ=cot3θ, then the value of sin2θ be: (a) \(\cfrac{1}{√2}\) (b) \(\cfrac{√3}{2}\) (c) \(\cfrac{1}{2}\) (d) 0
Answer: A
\(tanθ=cot3θ= tan⁡(90°-3θ)\)
\(∴θ=90°-3θ\)
or, \(θ+3θ=90° \)
or, \(4θ=90°\)
or, \(2θ=45°\)
∴ \(sin2θ=sin45°= \cfrac{1}{√2} \)
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